3.6.81 \(\int \frac {1}{x^{3/2} (a+b x)^{3/2}} \, dx\) [581]

Optimal. Leaf size=39 \[ \frac {2}{a \sqrt {x} \sqrt {a+b x}}-\frac {4 \sqrt {a+b x}}{a^2 \sqrt {x}} \]

[Out]

2/a/x^(1/2)/(b*x+a)^(1/2)-4*(b*x+a)^(1/2)/a^2/x^(1/2)

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Rubi [A]
time = 0.00, antiderivative size = 39, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {47, 37} \begin {gather*} \frac {2}{a \sqrt {x} \sqrt {a+b x}}-\frac {4 \sqrt {a+b x}}{a^2 \sqrt {x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x^(3/2)*(a + b*x)^(3/2)),x]

[Out]

2/(a*Sqrt[x]*Sqrt[a + b*x]) - (4*Sqrt[a + b*x])/(a^2*Sqrt[x])

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n +
1)/((b*c - a*d)*(m + 1))), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n + 1
)/((b*c - a*d)*(m + 1))), x] - Dist[d*(Simplify[m + n + 2]/((b*c - a*d)*(m + 1))), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rubi steps

\begin {align*} \int \frac {1}{x^{3/2} (a+b x)^{3/2}} \, dx &=\frac {2}{a \sqrt {x} \sqrt {a+b x}}+\frac {2 \int \frac {1}{x^{3/2} \sqrt {a+b x}} \, dx}{a}\\ &=\frac {2}{a \sqrt {x} \sqrt {a+b x}}-\frac {4 \sqrt {a+b x}}{a^2 \sqrt {x}}\\ \end {align*}

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Mathematica [A]
time = 0.06, size = 25, normalized size = 0.64 \begin {gather*} -\frac {2 (a+2 b x)}{a^2 \sqrt {x} \sqrt {a+b x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(x^(3/2)*(a + b*x)^(3/2)),x]

[Out]

(-2*(a + 2*b*x))/(a^2*Sqrt[x]*Sqrt[a + b*x])

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Mathics [A]
time = 2.62, size = 37, normalized size = 0.95 \begin {gather*} \frac {2 \sqrt {b} \left (-a-2 b x\right ) \sqrt {\frac {a+b x}{b x}}}{a^2 \left (a+b x\right )} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

mathics('Integrate[1/(x^(3/2)*(a + b*x)^(3/2)),x]')

[Out]

2 Sqrt[b] (-a - 2 b x) Sqrt[(a + b x) / (b x)] / (a ^ 2 (a + b x))

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Maple [A]
time = 0.14, size = 33, normalized size = 0.85

method	result	size
gosper	\(-\frac {2 \left (2 b x +a \right )}{\sqrt {x}\, \sqrt {b x +a}\, a^{2}}\)	\(22\)
default	\(-\frac {2}{a \sqrt {x}\, \sqrt {b x +a}}-\frac {4 b \sqrt {x}}{a^{2} \sqrt {b x +a}}\)	\(33\)
risch	\(-\frac {2 \sqrt {b x +a}}{a^{2} \sqrt {x}}-\frac {2 b \sqrt {x}}{a^{2} \sqrt {b x +a}}\)	\(33\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^(3/2)/(b*x+a)^(3/2),x,method=_RETURNVERBOSE)

[Out]

-2/a/x^(1/2)/(b*x+a)^(1/2)-4*b/a^2*x^(1/2)/(b*x+a)^(1/2)

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Maxima [A]
time = 0.26, size = 32, normalized size = 0.82 \begin {gather*} -\frac {2 \, b \sqrt {x}}{\sqrt {b x + a} a^{2}} - \frac {2 \, \sqrt {b x + a}}{a^{2} \sqrt {x}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(3/2)/(b*x+a)^(3/2),x, algorithm="maxima")

[Out]

-2*b*sqrt(x)/(sqrt(b*x + a)*a^2) - 2*sqrt(b*x + a)/(a^2*sqrt(x))

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Fricas [A]
time = 0.30, size = 34, normalized size = 0.87 \begin {gather*} -\frac {2 \, {\left (2 \, b x + a\right )} \sqrt {b x + a} \sqrt {x}}{a^{2} b x^{2} + a^{3} x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(3/2)/(b*x+a)^(3/2),x, algorithm="fricas")

[Out]

-2*(2*b*x + a)*sqrt(b*x + a)*sqrt(x)/(a^2*b*x^2 + a^3*x)

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Sympy [A]
time = 0.88, size = 41, normalized size = 1.05 \begin {gather*} - \frac {2}{a \sqrt {b} x \sqrt {\frac {a}{b x} + 1}} - \frac {4 \sqrt {b}}{a^{2} \sqrt {\frac {a}{b x} + 1}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**(3/2)/(b*x+a)**(3/2),x)

[Out]

-2/(a*sqrt(b)*x*sqrt(a/(b*x) + 1)) - 4*sqrt(b)/(a**2*sqrt(a/(b*x) + 1))

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Giac [A]
time = 0.00, size = 73, normalized size = 1.87 \begin {gather*} 2 \left (-\frac {\frac {1}{2}\cdot 2 b \sqrt {x} \sqrt {a+b x}}{a^{2} \left (a+b x\right )}+\frac {4 \sqrt {b}}{2 a \left (\left (\sqrt {a+b x}-\sqrt {b} \sqrt {x}\right )^{2}-a\right )}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(3/2)/(b*x+a)^(3/2),x)

[Out]

-2*b*sqrt(x)/(sqrt(b*x + a)*a^2) + 4*sqrt(b)/(((sqrt(b)*sqrt(x) - sqrt(b*x + a))^2 - a)*a)

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Mupad [B]
time = 0.39, size = 39, normalized size = 1.00 \begin {gather*} -\frac {2\,a\,\sqrt {a+b\,x}+4\,b\,x\,\sqrt {a+b\,x}}{\sqrt {x}\,\left (a^3+b\,x\,a^2\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^(3/2)*(a + b*x)^(3/2)),x)

[Out]

-(2*a*(a + b*x)^(1/2) + 4*b*x*(a + b*x)^(1/2))/(x^(1/2)*(a^3 + a^2*b*x))

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